Setting a different jdk version in settings.json (workspace) #1431

Environment

• Operating System: Windows 10
• JDK version: Multiple JDK (Java Home is Java1.8)
• Visual Studio Code version: 1.44.2
• Java extension version: 0.61.0

Steps To Reproduce

• I created a simple java hello world project.
• I setup my java.home in settings.json (workspace) to

{
    "java.home": "C:\\Program Files\\Java\\jdk11.0.2",
    "java.configuration.runtimes": [
        {
          "name": "JavaSE-1.8",
          "path": "C:\\Program Files\\Java\\jdk1.8.0_121",
        },
        {
          "name": "JavaSE-11",
          "path": "C:\\Program Files\\Java\\jdk11.0.2",
          "default": true
        }
      ]
}

because I want to use Java11.

• Java version in my environmental variables is set to C:\\Program Files\\Java\\jdk1.8.0_121.

As per the instruction posted here: https://github.com/redhat-developer/vscode-java#setting-the-jdk, vscode will use the workspace settings.json.

But when I tried running/debugging my application it has an error:

$  C:\Users\userX\.vscode\extensions\vscjava.vscode-java-debug-0.25.1\scripts\launcher.bat "C:\Program Files\Java\jdk1.8.0_121\bin\java.exe" -agentlib:jdwp=transport=dt_socket,server=ntlib:jdwp=transport=dt_socket,server=n,suspend=y,address=localhost:54576 -Dfile.encoding=UTF-8 -cp C:\test\test-java11\bin app.App
bash: C:UsersuserX.vscodeextensionsvscjava.vscode-java-debug-0.25.1scriptslauncher.bat: command not found

Is this an existing issue or am I doing it wrong? Thank you!