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Generic type argument cannot be inferred by nested callback return type #9660
Description
Activity
A similar (but not the same) situation: http://stackoverflow.com/questions/35613446/type-inference-for-functions-passed-to-generic-function-wrappers-like-debounce
You can simplify your issue:
declare function a<T>(f: (x: T) => T): T; a<number>(x => 1); // works a(x => 1); // infers T as { }
Thanks, then it's dup of #9659. Closing this.
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on Jun 19, 2018
TypeScript Version: 1.8.10
Code
Expected behavior:
In
a(x => y => 1),Tis inferred asnumberbased on nested callback return type.As shows
a<string>(x => y => 1)example, the just cannot be anything else.Actual behavior:
In
a(x => y => 1),Tis inferred as{ }.